Sum of an even number and the succeeding 4th even number is 48. Find the number.
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Let:
x= the 1st con.even number
x+2=the 2nd con.even number
x+4=the 3rd con.even number
Add the terms and equate it with the total, 48
x+(x+2)+(x+4)=48 , simplify
x+x+2+x+4=48 , combine like terms
3x+6=48 , isolate x
x=48−6/3 , find the value of x
x=14
The 3 con.even numbers are the following:
x=14
→ the smallest number
x+2=16
x+4=18
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