Question

Sum of any three consecutive numbers is always divisible by 3.​

Answer 1

Answer:

True

Step-by-step explanation:

let the first number be x.

Then the three consecutive numbers would be : x, x+1, x+2

Their sum is

$x + (x + 1) + (x + 2) \\ = 3x + 3 \\ = 3(x + 1)$

So we can see here x+1 is divisible by 3 making their addition divisible by 3. But the numbers must be whole.

Answer 2

Answer:

Yes because it is three consecutive digits

Ex 1+2+3=6

5+6+7=18

900+1000+1100=3000