Sum of area of 2 square is 544cm^ {2}. difference of their perimeter is 32 cm. find the sides of both the squares
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Answer:
a2+b2=544
4a-4b=32 --) a-b=8
(a-b)2=a2+b2-2ab
8*8=544-2ab
2ab=480
ab=240
a-b=8
a=12,-20
No negative vales so a=12
ab=240
b=240/12
b=20
Step-by-step explanation:
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