Sum of area of two square is 260m^2 if the difference of their perimeter is 24m then find the side of the square
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let side of first square = x
side of second square = y
sum of area of two square = 260 sq m
i.e x^2 + y^2 = 260 (i)
now the difference of their perimeter = 24 m
i.e 4x - 4y = 24
=> x - y = 6 (ii) (taken 4 common)
squarring equation (ii)
(x - y)^2 = 6^2
x^2 + y^2 - 2 xy = 36
260 - 2 xy =36 (value from equation (i)
224 - 2 (6+y) y =0 (value from equation (ii)
2y^2 + 12 y - 224 = 0 (multiplying both side with -1)
y^2 +6y - 112 =0
y^2 + 14 y - 8y - 112 = 0
y (y+14) - 8 (y+14) =0
y= 8 or -14 m
here we take positive number
so y= 8
therefore x-y = 6
=> x= 6+8 = 14 m
thus , the side of small square is 8m.
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