Question

sum of area of two square is 640 m2 .if difference of their perimeter is 64m find sides of two square

Answer 1

Answer:

24 and 8

Step-by-step explanation:

let the side of the larger square be x and smaller be y.

area of square is (side)^2

therefore, x^2+y^2 = 640...............(given).....1

perimeter of square is 4(side)

therefore, 4x-4y=64 (given)

dividing by 4

x-y=16

therefore, x=16+y..............2

sub. 2 in 1

(16+y)^2+y^2=640

(a+b)^2=a^2+b^2+2ab

therefore, 256+y^2+32y=640

2y^2+32y-384=0

dividing by 2,

y^2+16y-192=0

y^2+24y-8y-192=0

y(y+24)-8(y+24)

(y-8)(y+24)

therefore,y=8 or, y=-24

y=8(rejecting -ve)

x-y=16 (given above)

x-8=16

x=24

hope its helpful to you..........