Question

Sum of area of two square is 841 and difference of thier perimeter is 4 then find its sides

Answer 1

Answer:

x square +y square=841

(4x-4y=4)/4

x-y=1

x=1+y substitute this in first equation

(1+y)2+y2=841

y2+1+2y+y2=841

2y2+2y=840 dividing the whole equation by 2 we get,

y2+y-420=0

y2+21y-20y-420=0

y(y+21)-20(y+21)=0

(y-20)(y+21)

y=20 0r y=-21

then x=20+1=21

therefore the sides of square are 21 and 20

Step-by-step explanation: