Question

sum of areas of 2 sqares is 468msqaure if distance of their perimeter is 24 m then find the sides of two square

Answer 1

sum of areas,
x²+y²= 468 -------------1
now, difference between their perimeters,
4x-4y=24
x-y=6
x=y+6 --------------2
put this in eq1
(y+6)² + y² = 468
2y²+12y-432=0
here we get,
y=12m
so, x= 12+6= 18m

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