sum of areas of 2 squares =468 m^2,if the difference of their perimeter=24 cm. formulate quadratic equation.
Answers
Answered by
2
Step-by-step explanation:
4a-4b =24
a-b= 6. eq1
a^2 +b^2 = 468
(a+b)(a-b)=468
a+b= 468/6
a+b= 78 eq2
solving EQ 1 and 2 we get
a= 42,b= 36
x^2 + 78x + 42×36 = 0
last line question I didn't got so this result might be your answer
Similar questions