Question

sum of areas of 2 squares =468 m^2,if the difference of their perimeter=24 cm. formulate quadratic equation.

Answer 1

Step-by-step explanation:

4a-4b =24

a-b= 6. eq1

a^2 +b^2 = 468

(a+b)(a-b)=468

a+b= 468/6

a+b= 78 eq2

solving EQ 1 and 2 we get

a= 42,b= 36

x^2 + 78x + 42×36 = 0

last line question I didn't got so this result might be your answer