Question

sum of areas of 2 squares is 244 cm^2 and difference between their perimeter is 8 then find the ratio of their diagonals​

Answer 1

6 by 5 answer

this is a correct answer

Answer 2

Answer:6:5

Step-by-step explanation:

Consider 2 squares of side x and y (x>y) sum of their areas=244

x^2+y^2=244 also 4x-4y=8

x-y=2

x=2+y

substituting this in other equation

(2+y)^2+y^2=244

4+4y+y^2+y^2=244

2y^2+4y-240=0

y^2+2y-120=0

y^2+12y-10y-120=0

y(y+12)-10(y+12)=0

(y-10)(y+12)=0

y-10=0,y+12=0

y=10,y=(-12)

since we are looking for a positive value for y we eliminate y=(-12)

x=2+10=12

by the pythagoras theorem diagonals of squares with side x and y will be xroot2 and yroot2 respectively

ratio of their diagonals will be xroot2:yroot2

=x:y

=12:10

=6:5