Question

Sum of areas of two square is 400 cmsaquare if the difference of their perimeter is 16 cm find the each side

Answer 1

Let the side of 1st square be a

let the side of 2nd square be b

a^{2} + b^{2} = 400

a - b = 16

a = b + 16

(b + 16)^{2} + b^{2} = 400

2b^{2} + 32b + 256 = 400

2b^{2} + 32b - 144 = 0

then factorise and find the values of a and b