sum of areas of two square is 640 m2 .if the difference of their perimeter is 16 cm. find sides of two square?
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Side of the square be x and y
Now ar of two square =x sq and y sq
Sum =640
x sq +y sq =240. (1)
Now sum of perimeter =16
4x+4y=16
Dividing by 4 we get
x+y=4
y=4-x
Putting in (1)
X sq +(4-x)sq =640
Xsq +16+xsq-8x=640
2xsq -8x-624=0
Taking 2common
Xsq -4x-312=0
On solving the equation you will get the answer
Hope it helps you
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