Math, asked by 29GoblinsFromMars, 4 months ago

Sum of areas of two squares is 305 msquare

. If the difference of

their perimeters is 36m then find the sides of the two squares.​

Answers

Answered by tahelaniriya
1

Answer:

a=14. b=8.

Step-by-step explanation:

i hope it works

Answered by Anonymous
4

Answer:

the sum of area of two square is 41 metres. if the sum of their perimeter is 36 meters find the sides of the two squares.

given

sum of areas of 2 squares =41

let area of 1st square=a*2

area of 2nd square=b*2

a*2+b*2=41

sum of perimeters of 2squares=36

perimeter of 1st square=4a

perimeter of 2nd square=4b

4a+4b=36

koon

4(a+b)=36

a+b=36/4

a+b=9

a=9-b

we know that

a*2+b*2=41

(9-b) *2+b*2=41

81+b*2-18b+b*2=41

2b*2-18b=41-81

2b*2-18b=-40

2b*2-18b+40=0

b*2-9b+20=0

b*2-4b-5b+20=0

b(b-4)-5(b-4)=0

(b-4)(b-5)=0

b=4 b=5

a=9-4

a=5

length of sides of 2 squares=4m ,5m.

Step-by-step explanation:

#Hope you have satisfied with this answer.

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