Question

Sum of areas of two squares is 400 diff in perimeter is 16 find sides

Answer 1

Given

sum of areas=400

difference in perimeter=16

Let the sides of first and second square be 'x' and 'y' respectively.Then, according to question,

x^2+y^2=400.......(I)

4x-4y=16

or,x-y=4.........(ii)

or,x=4+y.........(iii)

From(I) and (ii),

(x-y)^2+2xy=400

or,4^2+xy=400

or,16+xy=400

or,xy=400-16

or,xy=384

or,x=384÷y........(iv)

From iii and iv,

4+y=384÷y

Solve it yourself from here, you will get two values of y.Then substitute both values in iii and get x, it will be your answer.