Question

sum of areas of two squares is 468 metre square if the difference of their perimeter is 24 m find the sides of the 2 squares​

Answer 1

Step-by-step explanation:

let the side of two squares be x and y

Now,

${x}^{2} + {y}^{2} = 468$

4x - 4y = 24

x - y = 6

x = 6+y

put x = 6+y in first equation,

${(6 + y)}^{2} + {y}^{2} = 468 \\ 36 + {y}^{2} + 12y + {y}^{2} = 468 \\ 2 {y}^{2} + 12y - 432 = 0 \\ {y}^{2} + 6y - 216 = 0$

after solving the above equation you will get the values of y and hence the value of x.

Answer 2

Step-by-step explanation:

hope it helps

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