sum of arithmetic progressions 50,46,42,...........to10terms
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Answered by
13
sum=n/2(2a+(n-1)d)
n=10. a=50. d=-4
10/2(100+(9)-4)=5*100-36=5*64=320
hope it helps!!
n=10. a=50. d=-4
10/2(100+(9)-4)=5*100-36=5*64=320
hope it helps!!
Answered by
8
Heya mate....
50,46,42,......10 terms....
An=a+(n-1)d
Here n=10.....a=50.....d=-4
Therefore An=59-36=23
Sn=n/2[a+l]
=5[50+23]
=365
@skb
50,46,42,......10 terms....
An=a+(n-1)d
Here n=10.....a=50.....d=-4
Therefore An=59-36=23
Sn=n/2[a+l]
=5[50+23]
=365
@skb
rk593371gmailcom:
apka galat hai
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