Question

Sum of between 200 and 800 that can be divided by 9

Answer 1

Step-by-step explanation:

the sum of 200 and 800 are 1000

and divided by 9

1000/9 ans 111.11

Answer 2

Answer:

First number = 207

last number = 792

An = a+(n-1)d

792 = 207+(n-1)9

792 = 198+9n

9n = 594

n = 66

$\boxed{Sum}$ = n/2(first term + Last term)

$\boxed{</em></strong><strong><em>Sum</em></strong><strong><em>}$ = 66/2(207+792) = 33*999 = 32,967

$\color{red}{Mark\: as\: Brainlist}$