Sum of cube of first 10 natural numbers will
be
explain me in deep
Answers
Answered by
1
Answer:
Sum of the cube of first ten natural numbers :
.i.e., 1^3 + 2^3 + 3^3 + _ _ _ _ +10^3
We know the sum of cubes of ( n ) natural numbers ( S ) = { n ( n + 1 ) / 2 }^2
Here n = 10
Therefore , the sum of cubes of first 10 natural numbers + { 10 ( 10+ 1 ) / 2 }^2
= {10 x 11 / 2 } ^2
= {110 / 2 }^2
= ( 55 )^2
= 3025
Answered by
0
Step-by-step explanation:
1,2,3,4,5,6,7,8,9,10 is the first 10 natural numbers
sum of 10 natural numbers is,
1=1x1=1
2=2x2=4
3=3x3=9
4=4x4=16
5=5x5=25
6=6x6=36
7=7x7=49
8=8x8=64
9=9x9=81
10=10x10=100
sum of cube of first 10 natural numbers is 1+4+9+16+25+36+49+64+81+100=385
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