Math, asked by dipikamodi53, 2 months ago

Sum of cube of first 10 natural numbers will
be
explain me in deep ​

Answers

Answered by stushamanth14651
1

Answer:

Sum of the cube of first ten natural numbers :

.i.e., 1^3 + 2^3 + 3^3 + _ _ _ _ +10^3

We know the sum of cubes of ( n ) natural numbers ( S ) = { n ( n + 1 ) / 2 }^2

Here n = 10

Therefore , the sum of cubes of first 10 natural numbers + { 10 ( 10+ 1 ) / 2 }^2

= {10 x 11 / 2 } ^2

= {110 / 2 }^2

= ( 55 )^2

= 3025

Answered by vekariyaRudra
0

Step-by-step explanation:

1,2,3,4,5,6,7,8,9,10 is the first 10 natural numbers

sum of 10 natural numbers is,

1=1x1=1

2=2x2=4

3=3x3=9

4=4x4=16

5=5x5=25

6=6x6=36

7=7x7=49

8=8x8=64

9=9x9=81

10=10x10=100

sum of cube of first 10 natural numbers is 1+4+9+16+25+36+49+64+81+100=385

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