sum of digit of teo number is 15 . reversing no. is 9 more than originql find the no
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Let the unit place digit be x
And tens place digit be 15-x
Original no.= 150-10x+x= 150-9x
By reversing digits,
New no.= 10x+15-x= 9x+15
According to question,
9x+15-(150-9x)= 9
9x+15-150-9x= 9
18x-135=9
18x= 144
x= 144/18
x= 8
So original no.= 150-9(8)= 150-72= 78
And tens place digit be 15-x
Original no.= 150-10x+x= 150-9x
By reversing digits,
New no.= 10x+15-x= 9x+15
According to question,
9x+15-(150-9x)= 9
9x+15-150-9x= 9
18x-135=9
18x= 144
x= 144/18
x= 8
So original no.= 150-9(8)= 150-72= 78
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