sum of digital of a two digit number is 11. If the digitals are interchange the number so got is 27 more than it. Find the numbers?
Answers
Answer:
The number is 47
Step-by-step explanation:
Let,
Units digit = x
Tens digit = 11 - x
Original number :
⇒ 10 (11 - x) + x
⇒ 110 - 10x + x
⇒ 110 - 9x
If the digits are interchanged the number so got is 27 more than it
⇒ 10x + 11 - x
⇒ 10x - x + 11
⇒ 9x + 11
★ According to the Question :
⇒ (110 - 9x) + 27 = 9x + 11
⇒ 110 - 9x + 27 = 9x + 11
⇒ 110 + 27 - 9x = 9x + 11
⇒ 137 - 9x = 9x + 11
⇒ 137 - 11 = 9x + 9x
⇒ 126 = 18x
⇒ x = 126 / 18
⇒ x = 7
Units digit = 7
Tens digit = 11 - x
⇒ 11 - 7 = 4
Tens digit = 4
Therefore, the number is 47
Answer:
Question :-
- Sum of digital of a two digit number is 11. If the digitals are interchange the number so got is 27 more than it. Find the numbers?
Given :-
- Sum of digital of a two digit number is 11. If the digitals are interchange the number so got is 27 more than it.
Find Out :-
- Find the numbers?
Solution :-
Let :
- Tens digit be x.
- Ones digit be y.
- Original number = 10x + y
When digits are interchanged:
New number = 10y + x
Sum of two digit :
x + y = 11
x = 11 - y ---------(Eqn no 1)
When the digits are interchanged :
10x + y + 27 = 10y + x
Substituting the value of x from eqn (i) we get that ,
10(11 - y) + y + 27 = 10y + 11 - y
110 - 10y + y + 27 = 9y + 11
137 - 9y = 9y + 11
9y + 9y = 137 - 11
18y = 126
y = 126/18
y = 7
From the equation 1 we get,
x = 11 - y
Substituting the value of y = 7 in the equation no 1 we get,
x = 11 - 7
x = 4
Let's finding the original number:
Original number = 10x + y
Original number = 10(4) + 7
Original number = 40 + 7
Original number = 47
Therefore, the numbers is 47.