Question

Sum of digits of a 2 digit number is 9. The number obtained by interchanging the digits is 18 more than twice the original number. The original number is​

Answer 1

Answer:

81

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

The sum of a two digit number is 9 and nine times this number is twice the number obtained by reversing the order of the digits. What is the number?

The answer is 18.

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Let the tens digit be a, and the units digit be b.

a+b=9

9(10a+b)=2(10b+a)

90a+9b=20b+2a

88a=11b

88a11=11b11

b=8a

a+(8a)=9

9a=9

9a9=99

a=1

b=8a so b=8

So the number must be 18

Proof:

9(10+8)=2(80+1)

90+72=160+2

162=162

Q.E.D.

The two-digit number is 18.