Question

sum of digits of a number is 6 if 36 is added to the number its digits are reversed determine the number

Answer 1

★ Ello ★

here is your answer !!


let the unit digit be y


let the tens digit be x


according to question :-

sum of digit's is. 6


then ,

x + y = 6 -------------------(1)






number formed is => 10 x + y



again , digit's are reversed =>

10 y + x


now , according to question


10 x + y + 36 = 10 y + x


=> 9 ( x -y) = -36


x - y = -4. -----------------------(2)



from equation 1 and 2 we get




x+ y = 6
x - y = -4
=========

2x = 2

x = 1


therefore , y = 5


hence , the number is 10 x + y


=> 10 × 1 + 5

=> 15



hence , your answer is 15



hope it helps you dear !!


$thanks$

Answer 2

 hye

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let the number be xy

Sum of digits of a number is 6

=> x+y = 6 .......[1]

=>if 36 is added to the number its digits are reversed

=>let the number ate tens place = 10x

=> ones place = y

=> (10x +y)  +36 = 10y +x

=> 36 = 10y +x - 10x -y

=>36 = 9y - 9x 

=>4 = y -x  ...........[2]

=>y -x = 4 and y +x = 6

adding both we get 

=>y +y = 6+4

=>2y = 10

=>y is equal to 5

sun of the digits is 6

=>x +5 =6

=>x = 6-5

=>x = 1

the number is xy

since x is 1 and y is 5

=>the number is 15

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hope it helps u.