sum of digits of a number is 6. if 36 is added to the number, its digits are reversed. determine the number
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Let the one's digit be x and ten's digit be y.
Then the number becomes = 10 y + x
According to the question,
x + y = 6 --> ( i )
10 y + x + 36 = 10x + y
10y - 10x + x- y = - 36
9y - 9 x = - 36
9 ( y - x ) = - 36
y - x = - 36 / 9
y - x = - 4
x - y = 4 --> ( ii )
Adding both equations,
x + y + x - y = 6 + 4
2x = 10
x = 10 / 2 = 5
x = 5
Putting value of x in Eqn ( i ),
x + y = 6
5 + y = 6
y = 6 - 5 = 1
y = 1
Number = 10y + x
Number = 10 ( 1 ) + 5
Number = 15
Then the number becomes = 10 y + x
According to the question,
x + y = 6 --> ( i )
10 y + x + 36 = 10x + y
10y - 10x + x- y = - 36
9y - 9 x = - 36
9 ( y - x ) = - 36
y - x = - 36 / 9
y - x = - 4
x - y = 4 --> ( ii )
Adding both equations,
x + y + x - y = 6 + 4
2x = 10
x = 10 / 2 = 5
x = 5
Putting value of x in Eqn ( i ),
x + y = 6
5 + y = 6
y = 6 - 5 = 1
y = 1
Number = 10y + x
Number = 10 ( 1 ) + 5
Number = 15
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