Question

sum of digits of a two digit no.is 8. if thier digits are interchanged the new no. so formed exceeds the original no. by 18 find the original no.​

Answer 1

Answer:

Let the ones place be x

so the tens place is 8-x

So, the number is 10(8-x) + x

= 80-10x+x

= 80-9x (original number)

After interchanging the digits,

ones place = 8-x

tens place = x

So, the number became 10x+8-x

= 9x+8 (interchanged number)

So, according to the question,

$80 - 9x + 18 = 9x + 8$

$98 - 9x = 9x + 8$

$- 9x - 9x = 8 - 98$

$- 18x = - 90$

$x = \frac{ - 90}{ - 18}$

$x = 5$

So, the original number is 80-(9 x 5)

= 80-45

= 35

The original number is 35

hope it helps