Math, asked by anshithkajith7300, 2 months ago

Sum of digits of a two digit number is 11. If the digits are interchanged the number so got
is 27 more than it. Find the numbers ?

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Answered by RvChaudharY50
0

Given :- Sum of digits of a two digit number is 11. If the digits are interchanged the number so got is 27 more than it. Find the numbers ?

Answer :-

Let us assume that, the given two digits number is (10x + y) .

so,

→ x + y = 11 -------- Eqn.(1)

and,

→ (10y + x) - (10x + y) = 27

→ 10y - y + x - 10x = 27

→ 9y - 9x = 27

→ 9(y - x) = 27

→ y - x = 3 ------- Eqn.(2)

adding Eqn.(1) and Eqn.(2) ,

→ x + y + y - x = 11 + 3

→ 2y = 14

→ y = 7 .

putting value of y in Eqn.(1),

→ x + 7 = 11

→ x = 11 - 7 = 4 .

therefore,

→ Required number = 10x + y = 10*4 + 7 = 47 (Ans.)

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