Sum of digits of a two digit number is 11. If the digits are interchanged the number so got
is 27 more than it. Find the numbers ?
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Given :- Sum of digits of a two digit number is 11. If the digits are interchanged the number so got is 27 more than it. Find the numbers ?
Answer :-
Let us assume that, the given two digits number is (10x + y) .
so,
→ x + y = 11 -------- Eqn.(1)
and,
→ (10y + x) - (10x + y) = 27
→ 10y - y + x - 10x = 27
→ 9y - 9x = 27
→ 9(y - x) = 27
→ y - x = 3 ------- Eqn.(2)
adding Eqn.(1) and Eqn.(2) ,
→ x + y + y - x = 11 + 3
→ 2y = 14
→ y = 7 .
putting value of y in Eqn.(1),
→ x + 7 = 11
→ x = 11 - 7 = 4 .
therefore,
→ Required number = 10x + y = 10*4 + 7 = 47 (Ans.)
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