Question

sum of digits of a two digit number is 11 .if the digits are interchanged the number so got is 27 more than it. find the numbers

Answer 1

Answer:

HERE IS YOUR ANSWER

Step-by-step explanation:

Let’s represent the tens digit with ‘a,”

and the ones digit with ‘b.’The value of

this number is 10a + b; this number is 27

more than the number formed by the

same digits in the other order, so 10a + b

= 10b + a + 27.

The digit sum is 11; a + b=11, or b = 11 - a

.10a + b

= 10b + a + 2710a + (11 - a)

= 10(11 - a) + a + 2710a + 11 - a

= 110 - 10a + a + 279a + 11

= 110 - 9a + 279a + 11

= 137 - 9a18a + 11

= 13718a

= 126a

= 126/18a

= 7b = 11 - 7

= 4

So the original number is 74.

The sum of the digits is 7+4=11.

And if you reverse the digits you get 47; 47 + 27 = 74.