Question

sum of digits of a two digit number is 13 if the number is subtracted from the one obtained by interchanging the digits the result is 45 what is the number

Answer 1

Here is your solution

Given :-
The sum of two digit number is 13 .
if the number is subtracted from the one obtained by interchanging the digits the results is 45 .

Let
The two digits be x and y.

Number is 10x + y 

x + y = 13 (given)

y = 13 – x --------------1

A/q

10y + x – (10x + y) = 45

9y – 9x = 45

y – x = 5 --------------2

putting the value of y from equation 1 in eqn 2

13 – x – x = 5

13 – 2x = 5

2x = 8

x = 4✔

y = 13 – 4 = 9✔

The two-digit number = 10x + y = (10 × 4) + 9 = 49.

Hope it helps you.

Answer 2

Answer:

Step-by-step explanation:

Solution:-

Let the tens place digit be x

And the ones place digit be y.

Number = 10x + y

Changed Number = 10y + x

According to the Question,

⇒ x + y = 13 .... (i)

⇒ 10y + x − 10x - y = 45

⇒ 9(y - x) = 45

⇒ y - x = 5 ..... (ii)

Solving Eq (i) & (ii), we get

⇒ 2y = 18  

⇒ y = 18/2

⇒ y = 9

Putting y's value in Eq (i), we get

⇒ x + y = 13

⇒ x = 4

Hence, the required number is 49.