Sum of digits of a two digit number is 6. Four times this number is seven times the
number obtained by reversing the order of the digits. Find the number.
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Let the two digits be x and y
x+y=6----(1)
The number is 10x+y and reverse is 10y+x
4(10x+y)=7(10y+x)
40x+4y=70y+7x
33x-66y=0
x-2y=0-----(2)
From (1) &(2)
x+y=6
x-2y=0
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3y=6
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y=2
then, x=4
Hence the number is 42
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