Math, asked by Artgaryan, 1 year ago

Sum of digits of a two digit number is 8 if the number obtained by reversing the digits is 18 find the original number

Answers

Answered by shivani3155
4

Answer:

original number is 35

Step-by-step explanation:

let the tens digit = x

and once digit = y

x + y = 8 ----------(1)

number is formed 10x + y

reversing the digit

then number is formed 10y + x

10x + y + 18 = 10y + x

10x + y - 10y - x = -18

9x - 9y = -18

divide by 9

x - y = -2 -------------(2)

on adding eq. 1 and 2

x + y = 8

x - y = -2

2x + 0 = 6

x = 6/2

x = 3

put x in eq 1

x + y = 8

3 + y = 8

y = 8 - 3

y = 5

number is 10x + y

= 10 × 3 + 5 = 30 + 5

= 35

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