Sum of digits of a two digit number is 8 if the number obtained by reversing the digits is 18 find the original number
Answers
Answer:
original number is 35
Step-by-step explanation:
let the tens digit = x
and once digit = y
x + y = 8 ----------(1)
number is formed 10x + y
reversing the digit
then number is formed 10y + x
10x + y + 18 = 10y + x
10x + y - 10y - x = -18
9x - 9y = -18
divide by 9
x - y = -2 -------------(2)
on adding eq. 1 and 2
x + y = 8
x - y = -2
2x + 0 = 6
x = 6/2
x = 3
put x in eq 1
x + y = 8
3 + y = 8
y = 8 - 3
y = 5
number is 10x + y
= 10 × 3 + 5 = 30 + 5
= 35