Question

sum of digits of a two-digit number is 9 then we interchange the digits it is found that the resulting new number is greater than original number by 27 what is the two digit number?​

Answer 1

Answer:

let the number be 10a+b;a is the tens place and b is unit place.

after reversing, the number is 10b+a.

we have given that:

a+b=9

we can also write,a=9-b------(1)

and, 10a+b+27=10b+a

10a-a+27=10b-b

9a+27=9b

from (1)

9(9-b)+27=9b

81-9b+27=9b

108=18b

b=6

putting value of b in (1)

a=3

hence,

original number=10a+b=36

new number=10b+a=63