Sum of digits of a two-digit number is 9. when we interchange the digits, it is found that the resulting new number is greater than the original number by 27. what is the two-digit number?
Answers
Answered by
1609
Let the digits be x and y.
Then, x+y = 9
the original number is 10x+y.
On reversing, we get the new number as 10y+x
The new number is greater than the old number by 27, i.e.
(10y+x) - (10x+y) = 27
or 9y-9x = 27, or y-x = 3
and x+y = 9
Adding the two equations, we get 2y = 12 or y = 6.
Thus, x = 3.
Therefore, the original number is 36.
Then, x+y = 9
the original number is 10x+y.
On reversing, we get the new number as 10y+x
The new number is greater than the old number by 27, i.e.
(10y+x) - (10x+y) = 27
or 9y-9x = 27, or y-x = 3
and x+y = 9
Adding the two equations, we get 2y = 12 or y = 6.
Thus, x = 3.
Therefore, the original number is 36.
Answered by
423
Answer:
ans is 36
Step-by-step explanation:
let the digit be x and y
Then, x+y=9
the original no. is 10x +y
on reversing, we get the new no. as 10y+x
the new no. is greater than the old no. by 27, i.e..,
(10y+x)-(10x+y)=27
or 9y-9x=27, or y-x=3and x +y=9
adding the two equations, we get 2y=12 or y=6
Thus, x =3
Therefore, the original no. is 36
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