sum of digits of a two digit number is 9 when we interchange the digits it is found that the resulting new number is greater than the original number by 63 find the two digit number
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sum of two digit no =10x+9-x
now by interchanging digit we get
10x+9-x+63=10(9-x)+x
now you can solve
now by interchanging digit we get
10x+9-x+63=10(9-x)+x
now you can solve
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