Question

SUM OF DIGITS OF A TWO DIGIT NUMBERIS 12. IF 18 IS ADDED TO IT , THE DIGITS ARE REVERSED. FIND THE NUMBER

Answer 1

Step-by-step explanation:

ANSWER

Let the tens digit of the required number be x and the units digit be y. Then,

x+y=12 .........(1)

Required Number = (10x+y).

Number obtained on reversing the digits = (10y+x).

Therefore,

(10y+x)−(10x+y)=18

9y−9x=18

y−x=2 ..........(2)

On adding (1) and (2), we get,

2y=14⟹y=7

Therefore,

x=5

Hence, the required number is 57.

Answer 2

Answer::

Hope it helps

Explanation::

Plz mark me as brainliest plzz