Sum of digits of a two digit numbers is 12
On interchanging their digits, new number
formed will be 54 more than original
number. Find original number.
Answers
Step-by-step explanation:
Assumption: Let the two digit number be 10x + y.
x + y = 12 ______ equation i
10y + x = ( 10x + y ) + 54
=> x + 10y = 10x + y + 54
=> - 9x + 9y = 54
=> 9x - 9y = 54
=> 9 ( x - y ) = 54
=> x - y = 6 ________ equation ii
By elimination method :-
For eliminating y, eq i × 1 + eq ii × 1,
x + y = 12
+ x - y = 6
2x = 18
=> x = 9
Putting x = 9 in eq i,
x + y = 12
=> 9 + y = 12
=> y = 12 - 9
=> y = 3
Therefore, x = 9 and y = 3.
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Answer:
The Original Number is 39.
Step-by-step explanation:
Given :
Sum of the digits = 12
Number formed after reversing the digits = 54 more than the original number
To find :
The Original Number
Solution :
Original Number -
Let the Digits be -
- Units Place as x
- Tens Place as 10(12 - x)
10(12 - x) + x
120 - 10x + x
120 - 9x ....... [Original Number]
Number with Reversed Digits -
Let the Digits be -
- Units Place as (12 - x)
- Tens Place as 10(x)
10(x) + (12 - x)
10x + 12 - x
9x + 12 ....... [Number With Reversed Digits]
According to the Question -
Number formed after reversing the digits = 54 more than the original number
9x + 12 = (120 - 9x) + 54
9x + 12 = 174 - 9x
9x + 9x = 174 - 12
18x = 162
x = 162/18
x = 9
★ Original Number -
120 - 9x
120 - 9(9)
120 - 81
39
The Original Number is 39.
Verification:
Original number = 39
Number With Reversed Digits = 93
39 + 54 = 93
93 = 93
LHS = RHS
The Original Number is 39.