Question

sum of digits of two digit number is 6. when its digits interchange their position the number gets increased by 18.. what are the numbers​

Answer 1

Answer:

Let the unit digit be x then tens digit be 6-x

Now two digit number = (tens digit)10+unit digit

=(6-x)10+x

=60-10x+x

60-9x

According to the question ,we interchange the digits,i.e.unit digit at tens place and tens at unit place.

Then the new number=10x+6-x=9x+6

again according to the question ,new number is greater than the original number by 18

9x+6=60-9x+18

9x+9x=78-6

18x=72

x=72/18

x=4

Explanation:

Hence the original number =60-9x=60-9*4

60-36=24

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