sum of digits of two digit number is 9 when we interchange the digits is found that the resulting number is greater than the original number by 27 what is two digit number
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the real two digit number is- 36
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Let the tens place digit be a
And unit place digit be b
According to first condition,
a + b = 9 ------(1)
According to second condition,
(10b+ a) - (10a + b) = 27
=> 10b + a - 10a - b = 27
=> 9b - 9a = 27
=> b - a = 3 -----(2)
On adding equation 1 and 2, we get
2b = 12
=> b = 6
Now,
On substituting the value of b in equation 1, we get
a + 6 = 9
=> a = 3
Required number = 36
And unit place digit be b
According to first condition,
a + b = 9 ------(1)
According to second condition,
(10b+ a) - (10a + b) = 27
=> 10b + a - 10a - b = 27
=> 9b - 9a = 27
=> b - a = 3 -----(2)
On adding equation 1 and 2, we get
2b = 12
=> b = 6
Now,
On substituting the value of b in equation 1, we get
a + 6 = 9
=> a = 3
Required number = 36
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