Question

Sum of digits of two digits number is 8. The digit in tens place is thrice the digit in unit

place. Find the number.​

Answer 1

ANSWER:

• Required number = 62

GIVEN:

• Sum of digits of two digits number is 8.
• The digit in tens place is thrice the digit in unit

TO FIND:

• Number

SOLUTION:

Let the digit at tens place be 'x'.

Let the digit at once place be 'y'.

Original number = 10x+y

CASE 1

=> x+y = 8 ....(I)

CASE 2

=> x = 3y. .....(ii)

Putting x = 3y in eq(i) we get;

=> 3y+y = 8

=> 4y = 8

=> y = 8/4

=> y = 2

Putting y = 2 in eq(I) we get;

=> x+2 = 8

=> x = 8-2

=> x = 6

Original number = 10x+y

= 10(6)+2

= 60+2

= 62

Answer 2

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Given:

• We have been given that the sum of twi digits number is 8.
• The digit of tens place is thrice the digit on ones place.

To Find:

• We need to find the number.

Solution:

Let us assume that the digit at tens place is x and the digit at ones place is y.

So, the number becomes 10x + y

Now according to the question, the sum of digits is 8, therefore

x + y = 8________(1)

Also, the digit at tens place is thrice the digit on ones place, so

x = 3y__________(2)

Now, substituting the value of x = 3y from equation 2 in equation, we have

3y + y = 8

=> 4y = 8

=> y = 8/4

=> y = 2________(3)

Now, substituting the value of y = 2 in equation 1, we have

x + 2 = 8

=> x = 8 - 2

=> x = 6________(4)

Therefore, the original number is, 10x + y.

Now substituting the value of x and y from equation 3 and 4 in 10x + y, we have

10(6) + 2

= 60 + 2

= 62

Hence, the required number is 62.