Question

Sum of even numbers and sum of odd numbers Arun and Kalai were playing a puzzle game with a given set of numbers. They need to find the odd and even numbers and find the sum of the odd numbers and the sum of the even numbers. Write a program to help them to solve the puzzle game and to win the mobile phone. Input Format: Input consists of n+1 integers. The first integer corresponds to ‘n’, the size of the array. The next ‘n’ integers correspond to the elements in the array. Assume that the maximum value of n is 15. Output Format: Refer to sample output for details.

Answer 1

Answer:

Sum of odd numbers =

$sum \: of \: odd \: numbers \: = \: {n}^{2}$

sum of even numbers= n(n(1)

Answer 2

Answer:

#include <iostream>

using namespace std;

int main()

{

int size;

cin>>size;

int i, num[15];

int oddSum=0,evenSum=0;

for(i=0;i<size;i++)

cin>>num[i];

for(i=0; i<size; i++)

{

if(num[i]%2==0)

evenSum=evenSum+num[i];

else

oddSum=oddSum+num[i];

}

cout<<"The sum of the even numbers in the array is "<< evenSum;

cout<<"\nThe sum of the odd numbers in the array is "<<oddSum;

return 0;

}

Explanation: