Sum of father and son ages is 42.After 4 years the age of father is 4 times the age of the son.Find their present age
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Let Son Age After 4 years=x years
Let Father Age After 4 years=4x years
Their Present Age will be
Son=(x-4) years
Father=(4x-4) years
(Why we subtract As If you are 14 years after 4 years You will 18 but To find present age
Subtract=18-4=14)
Now
Sum of their Ages=42
A/Q
(4x-4)+(x-4)=42
4x-4+x-4=42
5x-8=42
5x=42+8
5x=50
X=50/5
x=10
Son Present age=x-4=10-4=6 years
Father Present age=4x-4=40-4=36 years
Father=36 years
Son=6 years
Let Father Age After 4 years=4x years
Their Present Age will be
Son=(x-4) years
Father=(4x-4) years
(Why we subtract As If you are 14 years after 4 years You will 18 but To find present age
Subtract=18-4=14)
Now
Sum of their Ages=42
A/Q
(4x-4)+(x-4)=42
4x-4+x-4=42
5x-8=42
5x=42+8
5x=50
X=50/5
x=10
Son Present age=x-4=10-4=6 years
Father Present age=4x-4=40-4=36 years
Father=36 years
Son=6 years
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