Math, asked by atishaya04, 11 months ago

sum of first 10 natural numbers​


NeelamG: a = 1, d = 1 , n = 10
NeelamG: S10 = 10/2[1+10]
NeelamG: 5×11 = 55

Answers

Answered by Anonymous
0

 \frac{10 \times 11}{2}  = 55

Answered by Anonymous
11

HOLA

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FIRST 10 NATURAL NUMBER ARE---} 1,2,3,4,5,6,7,8,9,10

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SUM

1+2+3+4+5+6+7+8+9+10=55

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HOPE IT HELP

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