sum of first 10 terms of AP 3, 11, 19 is
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Here, a=3, d=11-3=8
S₁₀ = 10/2 [2 x 3 + 9 x 8] = 5 [6+72] = 5 x 78 = 390
Answered by
0
Given:a=3
d=11-3=8
Sum=10/2(2(3)+9(8))
=5*78
=390
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