Question

sum of first 100 term of arithmetic sequence 2,6,10

Answer 1

Answer:

sn=20000

Step-by-step explanation:

n=100

a=2

d=a2-a1=6-2=4

sn=n/2(2a+(n-1)d)

   =100/2[2(2)+(100-1)4]

   =100/2[4+99(4)]

   =100/2[4+396]

  =100/2[400]

  =100(200)

  =20000