Question

sum of first 100 terms of an arithmetic progression is 20000 then the sum of the squares of these 100 terms is​

Answer 1

Answer:

What is the sum of the first 100 terms of the arithmetic sequence 2, 6, 10, and 14?

Solution: N = 100, a = 2, d = 4

S100 = (100/2)[2*2 + 99*4]

= (100/2)[4+396]

= (100/2)(400)

= 20,000. Answer.

Answer 2

Answer:

The answer is :- 20000

Step-by-step explanation:

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