sum of first 101 terms are 1100 . find t51
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Step-by-step explanation:
According to the question:--
n/2(2a+(n-1)d)=Sn
101/2(2a+(101-1)d)=1100
101/2(2a+100d)=1100
101(a+50d)=1100
a+50d=1100/101
a+(51-1)d=1100/101
T51=1100/101
HOPE U UNDERSTOOD
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