sum of first 11 term of Ap is 19 is sum if first 19term is 11 find of sum of first 3oterm d.
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Answer:
-36480/143
If the question is true, then
Step-by-step explanation:
let, 1st term = a, common difference = d
Given,
S11 = 19, t19 = 11, then S30 = ?
Now,
t19 = a+18d = 11. ---eqⁿ1
S11 = 11/2.[2a+10d] = 19
or, 2a+10d = 38/11
or, a+5d = 19/11. ---eqⁿ2
On solving both the equations,
a = -263/143 and d = 102/143
Now,
S30 = 30/2[2x(-263/143) + 29x102/143]
= 15x[-526/143+2958/143]
= 15x-2432/143 = -36480/143.
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