sum of first 11 terms of arithmetic progression is 44 and the sum of next 11 terms is 55 find sequence
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sequence of 4 and 5 in your questions
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S = ½(2a1 + d(n-1))n
44 = ½(2a + d(10))11,
8=2a+10d
9 = (2a + d(21))
9=2a+21d,
8=2a+10d
9=21d
8=10d
1=11d
1/11=d
8=2a+10d
8=2a+10/11
4=a+5/11
39/11=a
first term is 39/11
difference is 10/11
sequence is 39/11 , 49/11 , 59/11 -------------------
khushboomeena:
than you so much for marking as a brainliest answer
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