sum of first 11terms of an A.P is 44 and that of later 11 term is 55 find AP
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Answer:
given
S11=44
S23=55
S11= 11/2(2a+10d)=44
=2a+10d=88/11
=a+5d=8.....eq1
S23= 22/2(2a+21d)=55
=2a+21d=110/22
=2a+21d=5....eq2
by eq1 and eq2
a=13 and d= -1
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