sum of first 12termd of AP
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Answered by
1
Answer:
tn=a+(n-1)d
t12=10+(12-1)6
t12=10 +66
t12=76
Step-by-step explanation:
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Answered by
0
Answer:
s12= 1/2 | 2a + (n-1)d|
s12 = 12/2 | 2×10 + (12-1)6|
s12 = 6|20+66|
s12 = 6×86
s12 = 516
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