Sum of first 15 terms of the series 1,3,5, 7............ is
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1+3+5+7+9+11+13+15+17+19+21+23+25+27+29= 225
sum of first n odd no is n^2
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Required sum is 225.
Step-by-step explanation:
Given series 1,3,5,7,......
First term of this series is 1 and common difference is (3-1)=2
and number of term is 15.
We know
Where
Number of terms.
First term of the series
Common difference
S is sum of n terms.
So, S=15/2[2X1+(15-1)x2]=15/2[2+28]=15/2x30=225
Some others formula of AP series are
an = a + (n – 1) × d
S = n/2[2a + (n − 1) × d
Sum of finite numbers of term= n/2(a + l)
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