Sum of first 2 terms is 32, sum of first 3 terms is 63. Find the 4th term.
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Answered by
1
Answer:
41
Step-by-step explanation:
If this is an A.P., then
Sn = n(2a + (n - 1)d)/2
S2
= 2(2a + d)/2
= 2a + d = 32 ----> eqn 1
S3
= 3(2a + 2d)/2
= 3a + 3d = 63
=> 2a + d + a + 2d = 63
32 + a + 2d = 63 (from eqn 1)
a + 2d = 31 ----> eqn 2
2*eqn 2 - eqn 1
=> 2a + 4d - (2a + d) = 62 - 32
=> 3d = 30
=> d = 10
an = a + (n - 1)d
a4
= a + 3d
= a + 2d + d
= 31 + d (from eqn 2)
= 31 + 10
= 41
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