Question

sum of first 200 even natural numbers​

Answer 1

Answer:

Hi There,

Address the formula, input parameters & values.

Input parameters & values:

The number series 2, 4, 6, 8, 10, 12, .  .  .  .  , 400.

The first term a = 2

The common difference d = 2

Total number of terms n = 200

step 2 apply the input parameter values in the AP formula

Sum = n/2 x (a + Tn)

= 200/2 x (2 + 400)

= (200 x 402)/ 2

= 80400/2

2 + 4 + 6 + 8 + 10 + 12 + .  .  .  .   + 400 = 40200

Therefore, 40200 is the sum of first 200 even numbers.

Hope It Helps!!!!!!!!!!!!!!!!!!!!

Answer 2

Answer:

40200

Explanation